LeetCode 「简单」21.合并两个有序链表

sankigan2025-2-25算法LeetCode

合并两个有序链表open in new window

题目描述

将两个升序链表合并为一个新的 升序 链表并返回。新链表是通过拼接给定的两个链表的所有节点组成的。

示例

输入:l1 = [1,2,4], l2 = [1,3,4]
输出:[1,1,2,3,4,4]

输入:l1 = [], l2 = []
输出:[]

输入:l1 = [], l2 = [0]
输出:[0]

解答

Code
/**
 * Definition for singly-linked list.
 * function ListNode(val, next) {
 *     this.val = (val===undefined ? 0 : val)
 *     this.next = (next===undefined ? null : next)
 * }
 */
/**
 * @param {ListNode} list1
 * @param {ListNode} list2
 * @return {ListNode}
 */
var mergeTwoLists = function(list1, list2) {
  const prehead = new ListNode(-1);
  let cur = prehead;
  let p1 = list1, p2 = list2;

  while (p1 || p2) {
    if (!p1) {
      cur.next = p2;
      p2 = p2.next;
    } else if (!p2) {
      cur.next = p1;
      p1 = p1.next;
    } else if (p1.val > p2.val) {
      cur.next = p2;
      p2 = p2.next;
    } else {
      cur.next = p1;
      p1 = p1.next;
    }

    cur = cur.next;
  }

  return prehead.next;
};
更新于 2025/3/20 23:23:29
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