LeetCode 「简单」226.翻转二叉树

sankigan2025-3-10算法LeetCode

翻转二叉树open in new window

题目描述

给你一棵二叉树的根节点 root ,翻转这棵二叉树,并返回其根节点。

示例

输入:root = [4,2,7,1,3,6,9]
输出:[4,7,2,9,6,3,1]

输入:root = [2,1,3]
输出:[2,3,1]

输入:root = []
输出:[]

解答

Code
/**
 * Definition for a binary tree node.
 * function TreeNode(val, left, right) {
 *     this.val = (val===undefined ? 0 : val)
 *     this.left = (left===undefined ? null : left)
 *     this.right = (right===undefined ? null : right)
 * }
 */
/**
 * @param {TreeNode} root
 * @return {TreeNode}
 */
var invertTree = function(root) {
  if (!root) return root;

  const temp = root.left;
  root.left = root.right;
  root.right = temp;

  invertTree(root.left);
  invertTree(root.right);

  return root;
};
更新于 2025/3/10 19:52:24
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